Skip to main content

Passing a user defined python object to C++ code(3)


How to access to the self.vertex_list.

This time I will explain how to access to the self.vertex_list of TriMesh. This is a list of length three numpy.array. We have already seen how to get the python list (dict's keylist) in my former article http://shitohichiumaya.blogspot.com/2010/08/boostpython-how-to-pass-python-object.html.

How to access to the float numpy.array element is the following.

void print_float32_3(boost::python::object const & float32_3_obj)
{
    // check sequence length is 3 or not.
    if(boost::python::len(float32_3_obj) != 3){
        std::string const objstr =
            boost::python::extract< std::string >(
                boost::python::str(float32_3_obj));
        std::cerr << "print_float32_3: arg is not a float[3] obj ["
                  << objstr << "]" << std::endl;
        return;
    }


    float vec[] = {0.0f, 0.0f, 0.0f};
    for(int i = 0; i < 3; ++i){
        vec[i] = boost::python::extract< float >(
            float32_3_obj.attr("__getitem__")(i));
    }
    std::cout << "float[3] = " << vec[0] << " " << vec[1] << " "
              << vec[2] << std::endl;
}

First, numpy.array is a sequence, therefore, we can ask length of it by boost::python::len(). We check the length is 3 or not since I defined it is three dimensional vector in the python code. Then we can access to each element through the attribute __getitem__. The python code puts float values to numpy.array, thus we can extract float value with extract< float >. Strictly speaking, numpy.array contains numpy.float64 instead of float, but, extract< float > still works here.

The last member of TriMesh, the triangle face index, should be done in the same way. Actually I would like to say that, but, there is a glitch here in numpy. We can not access this elements in the same way. We will get an errer:
TypeError: No registered converter was able to produce a C++ rvalue of type int from this Python object of type numpy.int64(). 
I would like to talk about this issue in the next blog.

Comments

Popular posts from this blog

Why A^{T}A is invertible? (2) Linear Algebra

Why A^{T}A has the inverse Let me explain why A^{T}A has the inverse, if the columns of A are independent. First, if a matrix is n by n, and all the columns are independent, then this is a square full rank matrix. Therefore, there is the inverse. So, the problem is when A is a m by n, rectangle matrix.  Strang's explanation is based on null space. Null space and column space are the fundamental of the linear algebra. This explanation is simple and clear. However, when I was a University student, I did not recall the explanation of the null space in my linear algebra class. Maybe I was careless. I regret that... Explanation based on null space This explanation is based on Strang's book. Column space and null space are the main characters. Let's start with this explanation. Assume  x  where x is in the null space of A .  The matrices ( A^{T} A ) and A share the null space as the following: This means, if x is in the null space of A , x is also in the null spa

Gauss's quote for positive, negative, and imaginary number

Recently I watched the following great videos about imaginary numbers by Welch Labs. https://youtu.be/T647CGsuOVU?list=PLiaHhY2iBX9g6KIvZ_703G3KJXapKkNaF I like this article about naming of math by Kalid Azad. https://betterexplained.com/articles/learning-tip-idea-name/ Both articles mentioned about Gauss, who suggested to use other names of positive, negative, and imaginary numbers. Gauss wrote these names are wrong and that is one of the reason people didn't get why negative times negative is positive, or, pure positive imaginary times pure positive imaginary is negative real number. I made a few videos about explaining why -1 * -1 = +1, too. Explanation: why -1 * -1 = +1 by pattern https://youtu.be/uD7JRdAzKP8 Explanation: why -1 * -1 = +1 by climbing a mountain https://youtu.be/uD7JRdAzKP8 But actually Gauss's insight is much powerful. The original is in the Gauß, Werke, Bd. 2, S. 178 . Hätte man +1, -1, √-1) nicht positiv, negative, imaginäre (oder gar um

Why parallelogram area is |ad-bc|?

Here is my question. The area of parallelogram is the difference of these two rectangles (red rectangle - blue rectangle). This is not intuitive for me. If you also think it is not so intuitive, you might interested in my slides. I try to explain this for hight school students. Slides:  A bit intuitive (for me) explanation of area of parallelogram  (to my site, external link) .